Frank,

There is an interesting feature of Schematron's design useful in a case like yours, namely that within a pattern, only one rule may apply to any element, and the first rule wins.

This means we can pre-empt the application of rules by writing other rules.

For example:

<sch:pattern id="Check_LI">

<sch:rule context="*[exists(@conref)]//li | li[exists(@conref)]"/>

<sch:rule context="li">

<sch:assert test="exists(*)">li must have children</sch:assert>

</sch:rule>

</sch:pattern>

The second rule says "an li must have children". The first rule intervenes for li elements that have @conref or an ancestor with @conref - it does no checking so it is silent.

Try it and see how it goes --

Cheers, Wendell

Hi all,

I need a Schemtron rule which indicates an error when <li> elements do not have any child elements. No error schould be indicated for <li> elements with an "conkeyref" attribute and also for <li> elements which are children of any element with a "conkeyref" attribute.

I have defined two separate rules...

<sch:pattern id="Check_LI2">
    <sch:rule context="li[not(@conkeyref)]">
      <sch:assert test="*">List does not contain any child elements</sch:assert>
    </sch:rule>
</sch:pattern>

<sch:pattern id="Check_LI3">
    <sch:rule context="li[not(parent::*[@conkeyref])]">
      <sch:assert test="*">List does not contain any child elements</sch:assert>
    </sch:rule>

</sch:pattern>

... but I think I need to combine them into a single rule with an OR or AND operator.

<sch:pattern id="Check_LI3">
    <sch:rule context="li[not(@conkeyref)] OR li[not(parent::*[@conkeyref])] ">
      <sch:assert test="*">List does not contain any child elements</sch:assert>
    </sch:rule>

</sch:pattern>

However, this syntax is invalid. Can somebody help me?

Regards,

Frank

--

Frank Dissinger

Documentation Manager

....................................................................

CGS Publishing Technologies International GmbH

Email frank.dissinger@cgs-oris.com | Web www.cgs-oris.com

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