[oXygen-user] Schematron rule

22 Feb 2023

      HI Wendell,

Thank you very much. Works like a charm.

Regards,

Frank

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Am 22.02.2023 um 14:22 schrieb Wendell Piez:
...
Frank,
There is an interesting feature of Schematron's design useful in a 
case like yours, namely that within a pattern, only one rule may apply 
to any element, and the first rule wins.
This means we can pre-empt the application of rules by writing other 
rules.
For example:
<sch:pattern id="Check_LI">
  <sch:rule context="*[exists(@conref)]//li | li[exists(@conref)]"/>
  <sch:rule context="li">
    <sch:assert test="exists(*)">li must have children</sch:assert>
  </sch:rule>
</sch:pattern>
The second rule says "an li must have children". The first rule 
intervenes for li elements that have @conref or an ancestor with 
@conref - it does no checking so it is silent.
Try it and see how it goes --
Cheers, Wendell
------------------------------------------------------------------------
On Wed, Feb 22, 2023 at 7:35 AM Frank Dissinger 
<frank.dissinger@cgs-oris.com> wrote:
Hi all,
I need a Schemtron rule which indicates an error when <li>
    elements do not have any child elements. No error schould be
    indicated for <li> elements with an "conkeyref" attribute and also
    for <li> elements which are children of any element with a
    "conkeyref" attribute.
I have defined two separate rules...
  <sch:pattern id="Check_LI2">
        <sch:rule context="*li[not(@conkeyref)]*">
          <sch:assert test="*">List does not contain any child
    elements</sch:assert>
        </sch:rule>
      </sch:pattern>
  <sch:pattern id="Check_LI3">
        <sch:rule context="*li[not(parent::*[@conkeyref])]*">
          <sch:assert test="*">List does not contain any child
    elements</sch:assert>
        </sch:rule>
  </sch:pattern>
... but I think I need to combine them into a single rule with an
    OR or AND operator.
  <sch:pattern id="Check_LI3">
        <sch:rule context="*li[not(@conkeyref)]* *OR
    **li[not(parent::*[@conkeyref])] *">
          <sch:assert test="*">List does not contain any child
    elements</sch:assert>
        </sch:rule>
  </sch:pattern>
However, this syntax is invalid. Can somebody help me?
Regards,
Frank
--
*Frank Dissinger*
Documentation Manager
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